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How do you solve equation of reducible in quadratic equations? - Answers

9x^4 -18x^2 + 5=0 Let y be x^2 9y^2-18y+5=0 (3y-5)(3y-1)=0 3y-5=0 or 3y-1=0 3x^2-5=0 3x^2-1=0 x^2=±√5/3 x=±1/√3

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How do you solve equation of reducible in quadratic equations? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_solve_equation_of_reducible_in_quadratic_equations

9x^4 -18x^2 + 5=0 Let y be x^2 9y^2-18y+5=0 (3y-5)(3y-1)=0 3y-5=0 or 3y-1=0 3x^2-5=0 3x^2-1=0 x^2=±√5/3 x=±1/√3

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https://math.answers.com/math-and-arithmetic/How_do_you_solve_equation_of_reducible_in_quadratic_equations

How do you solve equation of reducible in quadratic equations? - Answers

9x^4 -18x^2 + 5=0 Let y be x^2 9y^2-18y+5=0 (3y-5)(3y-1)=0 3y-5=0 or 3y-1=0 3x^2-5=0 3x^2-1=0 x^2=±√5/3 x=±1/√3

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  9x^4 -18x^2 + 5=0 Let y be x^2 9y^2-18y+5=0 (3y-5)(3y-1)=0 3y-5=0 or 3y-1=0 3x^2-5=0 3x^2-1=0 x^2=±√5/3 x=±1/√3
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