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How do you find the equation when all zeros are given? - Answers

Let's say y1, y2, and y3 are zeros. Set up an expression like this (x-y1)(x-y2)(x-y3) [This is factored form] and then multiply carefully. That works with any number of roots. If 0 is a root, add an x by itself to the beginning of the factored form expression. Also, imaginary roots come in twos. Therefore, if given i as a root, you need (x-i)(x+i). If you have something in x + yi form for a root, you'll need the complex conjugate. That would make (x-(a+bi))(x-(a-bi))



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How do you find the equation when all zeros are given? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_find_the_equation_when_all_zeros_are_given

Let's say y1, y2, and y3 are zeros. Set up an expression like this (x-y1)(x-y2)(x-y3) [This is factored form] and then multiply carefully. That works with any number of roots. If 0 is a root, add an x by itself to the beginning of the factored form expression. Also, imaginary roots come in twos. Therefore, if given i as a root, you need (x-i)(x+i). If you have something in x + yi form for a root, you'll need the complex conjugate. That would make (x-(a+bi))(x-(a-bi))



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https://math.answers.com/math-and-arithmetic/How_do_you_find_the_equation_when_all_zeros_are_given

How do you find the equation when all zeros are given? - Answers

Let's say y1, y2, and y3 are zeros. Set up an expression like this (x-y1)(x-y2)(x-y3) [This is factored form] and then multiply carefully. That works with any number of roots. If 0 is a root, add an x by itself to the beginning of the factored form expression. Also, imaginary roots come in twos. Therefore, if given i as a root, you need (x-i)(x+i). If you have something in x + yi form for a root, you'll need the complex conjugate. That would make (x-(a+bi))(x-(a-bi))

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      Let's say y1, y2, and y3 are zeros. Set up an expression like this (x-y1)(x-y2)(x-y3) [This is factored form] and then multiply carefully. That works with any number of roots. If 0 is a root, add an x by itself to the beginning of the factored form expression. Also, imaginary roots come in twos. Therefore, if given i as a root, you need (x-i)(x+i). If you have something in x + yi form for a root, you'll need the complex conjugate. That would make (x-(a+bi))(x-(a-bi))

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