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How do you find a missing divisor in a division problem? - Answers

You may switch some values around to solve a multiplication variable instead, although this is often just as difficult as solving a division problem. An example is 100/x=10 You may multiply x out on both sides so that the equation is simpler. For example: # 100/x=10 (Original equation) # Multiply x by both sides so that you get 100=10x (What you do to one side must be done to the other) # Divide both sides by 10 so that you get 10=x (Again, both sides are necessary) You then have your answer, x=10.



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How do you find a missing divisor in a division problem? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_find_a_missing_divisor_in_a_division_problem

You may switch some values around to solve a multiplication variable instead, although this is often just as difficult as solving a division problem. An example is 100/x=10 You may multiply x out on both sides so that the equation is simpler. For example: # 100/x=10 (Original equation) # Multiply x by both sides so that you get 100=10x (What you do to one side must be done to the other) # Divide both sides by 10 so that you get 10=x (Again, both sides are necessary) You then have your answer, x=10.



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https://math.answers.com/math-and-arithmetic/How_do_you_find_a_missing_divisor_in_a_division_problem

How do you find a missing divisor in a division problem? - Answers

You may switch some values around to solve a multiplication variable instead, although this is often just as difficult as solving a division problem. An example is 100/x=10 You may multiply x out on both sides so that the equation is simpler. For example: # 100/x=10 (Original equation) # Multiply x by both sides so that you get 100=10x (What you do to one side must be done to the other) # Divide both sides by 10 so that you get 10=x (Again, both sides are necessary) You then have your answer, x=10.

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      You may switch some values around to solve a multiplication variable instead, although this is often just as difficult as solving a division problem. An example is 100/x=10 You may multiply x out on both sides so that the equation is simpler. For example: # 100/x=10 (Original equation) # Multiply x by both sides so that you get 100=10x (What you do to one side must be done to the other) # Divide both sides by 10 so that you get 10=x (Again, both sides are necessary) You then have your answer, x=10.

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