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How do you factorise x cubed take one? - Answers

If it's (x3 -1) that you want to factorize, then find the solutions to (x3 -1) = 0.So if P(x) is a polynomial of x, and x=a is a solution for P(x) = 0, then (x - a) is a factor of P(x).So x = 1 solves (x3 -1) = 0, so (x - 1) is a factor. Use long division (x3 -1)/(x-1) = x2 + x + 1. Use the quadratic formula to find the roots of this: -1/2 ± i*sqrt(3)/2, which is complex. So the factorization is:(x3 -1) = (x - 1)( x2 + x + 1)Multiply the polynomials together to check that your answer is correct.



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How do you factorise x cubed take one? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_factorise_x_cubed_take_one

If it's (x3 -1) that you want to factorize, then find the solutions to (x3 -1) = 0.So if P(x) is a polynomial of x, and x=a is a solution for P(x) = 0, then (x - a) is a factor of P(x).So x = 1 solves (x3 -1) = 0, so (x - 1) is a factor. Use long division (x3 -1)/(x-1) = x2 + x + 1. Use the quadratic formula to find the roots of this: -1/2 ± i*sqrt(3)/2, which is complex. So the factorization is:(x3 -1) = (x - 1)( x2 + x + 1)Multiply the polynomials together to check that your answer is correct.



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https://math.answers.com/math-and-arithmetic/How_do_you_factorise_x_cubed_take_one

How do you factorise x cubed take one? - Answers

If it's (x3 -1) that you want to factorize, then find the solutions to (x3 -1) = 0.So if P(x) is a polynomial of x, and x=a is a solution for P(x) = 0, then (x - a) is a factor of P(x).So x = 1 solves (x3 -1) = 0, so (x - 1) is a factor. Use long division (x3 -1)/(x-1) = x2 + x + 1. Use the quadratic formula to find the roots of this: -1/2 ± i*sqrt(3)/2, which is complex. So the factorization is:(x3 -1) = (x - 1)( x2 + x + 1)Multiply the polynomials together to check that your answer is correct.

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      If it's (x3 -1) that you want to factorize, then find the solutions to (x3 -1) = 0.So if P(x) is a polynomial of x, and x=a is a solution for P(x) = 0, then (x - a) is a factor of P(x).So x = 1 solves (x3 -1) = 0, so (x - 1) is a factor. Use long division (x3 -1)/(x-1) = x2 + x + 1. Use the quadratic formula to find the roots of this: -1/2 ± i*sqrt(3)/2, which is complex. So the factorization is:(x3 -1) = (x - 1)( x2 + x + 1)Multiply the polynomials together to check that your answer is correct.

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