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How do you factor -3x2-6x plus 24? - Answers

-3(x-2)(x+4) is the answer. Here is how I got it: you can factor a -3 out immediately. That changes it to: x2+2x-8 Now, what two numbers multiply to -8 and add to 2? well, -2 and 4 (-2*4=-8, -3+4=2) So, since there is no coefficient on x^2 (actually it is assumed to be 1) Therefore, you write: (x-2)(x+4) then you put the -3 on the outside, as you factored it out before, giving you: -3(x-2)(x+4)



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How do you factor -3x2-6x plus 24? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_factor_-3x2-6x_plus_24

-3(x-2)(x+4) is the answer. Here is how I got it: you can factor a -3 out immediately. That changes it to: x2+2x-8 Now, what two numbers multiply to -8 and add to 2? well, -2 and 4 (-2*4=-8, -3+4=2) So, since there is no coefficient on x^2 (actually it is assumed to be 1) Therefore, you write: (x-2)(x+4) then you put the -3 on the outside, as you factored it out before, giving you: -3(x-2)(x+4)



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https://math.answers.com/math-and-arithmetic/How_do_you_factor_-3x2-6x_plus_24

How do you factor -3x2-6x plus 24? - Answers

-3(x-2)(x+4) is the answer. Here is how I got it: you can factor a -3 out immediately. That changes it to: x2+2x-8 Now, what two numbers multiply to -8 and add to 2? well, -2 and 4 (-2*4=-8, -3+4=2) So, since there is no coefficient on x^2 (actually it is assumed to be 1) Therefore, you write: (x-2)(x+4) then you put the -3 on the outside, as you factored it out before, giving you: -3(x-2)(x+4)

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      -3(x-2)(x+4) is the answer. Here is how I got it: you can factor a -3 out immediately. That changes it to: x2+2x-8 Now, what two numbers multiply to -8 and add to 2? well, -2 and 4 (-2*4=-8, -3+4=2) So, since there is no coefficient on x^2 (actually it is assumed to be 1) Therefore, you write: (x-2)(x+4) then you put the -3 on the outside, as you factored it out before, giving you: -3(x-2)(x+4)

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