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How do you derive Poisson's equation from Maxwell's equations? - Answers
Start with the differential form of Gauss's law:∇ â— E = Ï/ε0, the divergence of the electric field is equal to the total charge density divided by the permittivity of free space.Make the following substitution, assuming electrostatic charges:E = -∇φ, the electric field at a point is equal to the negative gradient of the scalar electric potential.This gives:∇ ◠∇φ = -Ï/ε0From an identity of vector calculus we get the following:∇2φ = -Ï/ε0, which is Poisson's equation with f = -Ï/ε0.
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How do you derive Poisson's equation from Maxwell's equations? - Answers
Start with the differential form of Gauss's law:∇ â— E = Ï/ε0, the divergence of the electric field is equal to the total charge density divided by the permittivity of free space.Make the following substitution, assuming electrostatic charges:E = -∇φ, the electric field at a point is equal to the negative gradient of the scalar electric potential.This gives:∇ ◠∇φ = -Ï/ε0From an identity of vector calculus we get the following:∇2φ = -Ï/ε0, which is Poisson's equation with f = -Ï/ε0.
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How do you derive Poisson's equation from Maxwell's equations? - Answers
Start with the differential form of Gauss's law:∇ â— E = Ï/ε0, the divergence of the electric field is equal to the total charge density divided by the permittivity of free space.Make the following substitution, assuming electrostatic charges:E = -∇φ, the electric field at a point is equal to the negative gradient of the scalar electric potential.This gives:∇ ◠∇φ = -Ï/ε0From an identity of vector calculus we get the following:∇2φ = -Ï/ε0, which is Poisson's equation with f = -Ï/ε0.
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- og:descriptionStart with the differential form of Gauss's law:∇ â— E = Ï/ε0, the divergence of the electric field is equal to the total charge density divided by the permittivity of free space.Make the following substitution, assuming electrostatic charges:E = -∇φ, the electric field at a point is equal to the negative gradient of the scalar electric potential.This gives:∇ ◠∇φ = -Ï/ε0From an identity of vector calculus we get the following:∇2φ = -Ï/ε0, which is Poisson's equation with f = -Ï/ε0.
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