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How do you convert an equation into a system? - Answers

you can convert Fermat's equation into a system. Assuming z^3=x^3+y^3. Mean [z(z+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+z^3]+[z(z+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+x^3+y^3]=[x(x+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+......+x^3]+[y(y+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+y^3] after simple, x^3 and y^3 have been lost , just rest z^3. number (a) can change unlimited This complex system have no solution integer.



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How do you convert an equation into a system? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_convert_an_equation_into_a_system

you can convert Fermat's equation into a system. Assuming z^3=x^3+y^3. Mean [z(z+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+z^3]+[z(z+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+x^3+y^3]=[x(x+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+......+x^3]+[y(y+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+y^3] after simple, x^3 and y^3 have been lost , just rest z^3. number (a) can change unlimited This complex system have no solution integer.



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https://math.answers.com/math-and-arithmetic/How_do_you_convert_an_equation_into_a_system

How do you convert an equation into a system? - Answers

you can convert Fermat's equation into a system. Assuming z^3=x^3+y^3. Mean [z(z+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+z^3]+[z(z+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+x^3+y^3]=[x(x+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+......+x^3]+[y(y+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+y^3] after simple, x^3 and y^3 have been lost , just rest z^3. number (a) can change unlimited This complex system have no solution integer.

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      you can convert Fermat's equation into a system. Assuming z^3=x^3+y^3. Mean [z(z+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+z^3]+[z(z+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+x^3+y^3]=[x(x+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+......+x^3]+[y(y+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+y^3] after simple, x^3 and y^3 have been lost , just rest z^3. number (a) can change unlimited This complex system have no solution integer.
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