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How do you calculate square root of a number? - Answers

One way to estimate the square root of a number is by iteration. This entails making a guess at the answer and then improving on it. Repeating the procedure should lead to a better estimate at each stage. One such is the Newton-Raphson method.If you want to find the square root of 7, define f(x) = x^2 – 7.Then finding the square root of 7 is equivalent to solving f(x) = 0.Let f’(x) = 2x. This is the derivative of f(x) but you do not need to know that to use the N-R method.Start with x0 as the first guess. Then let xn+1 = xn - f(xn)/f’(xn) for n = 0, 1, 2, … Provided you made a reasonable choice for the starting point, the iteration will very quickly converge to the true answer. It works even if your first guess is not so good:Suppose you start with x0 = 5 (a pretty poor choice since 5^2 is 25, which is nowhere near 7).Even so, x3 = 2.2362512515, which is less than 0.01% from the true value. Finally, remember that the negative value, -x, is also a square root.



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How do you calculate square root of a number? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_calculate_square_root_of_a_number

One way to estimate the square root of a number is by iteration. This entails making a guess at the answer and then improving on it. Repeating the procedure should lead to a better estimate at each stage. One such is the Newton-Raphson method.If you want to find the square root of 7, define f(x) = x^2 – 7.Then finding the square root of 7 is equivalent to solving f(x) = 0.Let f’(x) = 2x. This is the derivative of f(x) but you do not need to know that to use the N-R method.Start with x0 as the first guess. Then let xn+1 = xn - f(xn)/f’(xn) for n = 0, 1, 2, … Provided you made a reasonable choice for the starting point, the iteration will very quickly converge to the true answer. It works even if your first guess is not so good:Suppose you start with x0 = 5 (a pretty poor choice since 5^2 is 25, which is nowhere near 7).Even so, x3 = 2.2362512515, which is less than 0.01% from the true value. Finally, remember that the negative value, -x, is also a square root.



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https://math.answers.com/math-and-arithmetic/How_do_you_calculate_square_root_of_a_number

How do you calculate square root of a number? - Answers

One way to estimate the square root of a number is by iteration. This entails making a guess at the answer and then improving on it. Repeating the procedure should lead to a better estimate at each stage. One such is the Newton-Raphson method.If you want to find the square root of 7, define f(x) = x^2 – 7.Then finding the square root of 7 is equivalent to solving f(x) = 0.Let f’(x) = 2x. This is the derivative of f(x) but you do not need to know that to use the N-R method.Start with x0 as the first guess. Then let xn+1 = xn - f(xn)/f’(xn) for n = 0, 1, 2, … Provided you made a reasonable choice for the starting point, the iteration will very quickly converge to the true answer. It works even if your first guess is not so good:Suppose you start with x0 = 5 (a pretty poor choice since 5^2 is 25, which is nowhere near 7).Even so, x3 = 2.2362512515, which is less than 0.01% from the true value. Finally, remember that the negative value, -x, is also a square root.

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      One way to estimate the square root of a number is by iteration. This entails making a guess at the answer and then improving on it. Repeating the procedure should lead to a better estimate at each stage. One such is the Newton-Raphson method.If you want to find the square root of 7, define f(x) = x^2 – 7.Then finding the square root of 7 is equivalent to solving f(x) = 0.Let f’(x) = 2x. This is the derivative of f(x) but you do not need to know that to use the N-R method.Start with x0 as the first guess. Then let xn+1 = xn - f(xn)/f’(xn) for n = 0, 1, 2, … Provided you made a reasonable choice for the starting point, the iteration will very quickly converge to the true answer. It works even if your first guess is not so good:Suppose you start with x0 = 5 (a pretty poor choice since 5^2 is 25, which is nowhere near 7).Even so, x3 = 2.2362512515, which is less than 0.01% from the true value. Finally, remember that the negative value, -x, is also a square root.
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