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How do you add three mixed fractions? - Answers

Well, that's why we only use mixed fractions in solutions/answers because it is a hell to work with. But, there are tricks to do it. First, write mixed fractions as a combination of an integer and a proper fraction By integer, we mean whole numbers, - 1000, -1, 0, 6, 20 etc. By proper fraction, we mean a fraction p/q where both p and q are natural numbers, 1, 2, 3, 4, etc., they have no common factor and p <= q. Now we have three in such form, let's say a b/c, d e/f and g h/i Now, write them by their definition that is a b/c = a + b/c so the sum of all 3 is a + b/c + d + e/f +g + h/i Addition is commutable and associative, so rearrange the operation (a + d + g) + (b/c + e/f + h/i) a + d + g are justing three integers, and the other half is adding proper fractions, easy as pie! Let's say we get m = a + d + g and (o/p) = b/c + e/f + h/i, then the answer is obvious m o/p Oh, not so fast, we have to simplify o/p first --- first reduce it to lowest irreducible form, then write it in its mixed fraction form say, z x/y = o/p then we combine them we get (m + z) x/y is your solution. A lot of symbols, might get lost. Note: In higher calculations though, it is prefered never use mixed fractions operations because this trick will get very long. So the BEST way is to turn them into normal (non- proper/proper) fraction.



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How do you add three mixed fractions? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_add_three_mixed_fractions

Well, that's why we only use mixed fractions in solutions/answers because it is a hell to work with. But, there are tricks to do it. First, write mixed fractions as a combination of an integer and a proper fraction By integer, we mean whole numbers, - 1000, -1, 0, 6, 20 etc. By proper fraction, we mean a fraction p/q where both p and q are natural numbers, 1, 2, 3, 4, etc., they have no common factor and p <= q. Now we have three in such form, let's say a b/c, d e/f and g h/i Now, write them by their definition that is a b/c = a + b/c so the sum of all 3 is a + b/c + d + e/f +g + h/i Addition is commutable and associative, so rearrange the operation (a + d + g) + (b/c + e/f + h/i) a + d + g are justing three integers, and the other half is adding proper fractions, easy as pie! Let's say we get m = a + d + g and (o/p) = b/c + e/f + h/i, then the answer is obvious m o/p Oh, not so fast, we have to simplify o/p first --- first reduce it to lowest irreducible form, then write it in its mixed fraction form say, z x/y = o/p then we combine them we get (m + z) x/y is your solution. A lot of symbols, might get lost. Note: In higher calculations though, it is prefered never use mixed fractions operations because this trick will get very long. So the BEST way is to turn them into normal (non- proper/proper) fraction.



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https://math.answers.com/math-and-arithmetic/How_do_you_add_three_mixed_fractions

How do you add three mixed fractions? - Answers

Well, that's why we only use mixed fractions in solutions/answers because it is a hell to work with. But, there are tricks to do it. First, write mixed fractions as a combination of an integer and a proper fraction By integer, we mean whole numbers, - 1000, -1, 0, 6, 20 etc. By proper fraction, we mean a fraction p/q where both p and q are natural numbers, 1, 2, 3, 4, etc., they have no common factor and p <= q. Now we have three in such form, let's say a b/c, d e/f and g h/i Now, write them by their definition that is a b/c = a + b/c so the sum of all 3 is a + b/c + d + e/f +g + h/i Addition is commutable and associative, so rearrange the operation (a + d + g) + (b/c + e/f + h/i) a + d + g are justing three integers, and the other half is adding proper fractions, easy as pie! Let's say we get m = a + d + g and (o/p) = b/c + e/f + h/i, then the answer is obvious m o/p Oh, not so fast, we have to simplify o/p first --- first reduce it to lowest irreducible form, then write it in its mixed fraction form say, z x/y = o/p then we combine them we get (m + z) x/y is your solution. A lot of symbols, might get lost. Note: In higher calculations though, it is prefered never use mixed fractions operations because this trick will get very long. So the BEST way is to turn them into normal (non- proper/proper) fraction.

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      Well, that's why we only use mixed fractions in solutions/answers because it is a hell to work with. But, there are tricks to do it. First, write mixed fractions as a combination of an integer and a proper fraction By integer, we mean whole numbers, - 1000, -1, 0, 6, 20 etc. By proper fraction, we mean a fraction p/q where both p and q are natural numbers, 1, 2, 3, 4, etc., they have no common factor and p <= q. Now we have three in such form, let's say a b/c, d e/f and g h/i Now, write them by their definition that is a b/c = a + b/c so the sum of all 3 is a + b/c + d + e/f +g + h/i Addition is commutable and associative, so rearrange the operation (a + d + g) + (b/c + e/f + h/i) a + d + g are justing three integers, and the other half is adding proper fractions, easy as pie! Let's say we get m = a + d + g and (o/p) = b/c + e/f + h/i, then the answer is obvious m o/p Oh, not so fast, we have to simplify o/p first --- first reduce it to lowest irreducible form, then write it in its mixed fraction form say, z x/y = o/p then we combine them we get (m + z) x/y is your solution. A lot of symbols, might get lost. Note: In higher calculations though, it is prefered never use mixed fractions operations because this trick will get very long. So the BEST way is to turn them into normal (non- proper/proper) fraction.
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