Formula for triginometry? - Answers

Well, there are a few ways-A) You can go with Sine, Cosine, Tangent (Spelling?)And that works like this:Sine=O/H (Opposite over Hypotenuse I believe)Cosine=A/H (Adjacent side over Hypotenuse I believe)Tangent=O/A (Opposite over Adjacent side I believe)This is how you remember that:Sine=Oscar/HadCosine=A/HairyTangent=Old/A**B) You can do it the easy way (how I do it)- A right triangle goes like this: The legs are A and B, and the hypotenuse is C. This is where we start.A=BA=C/ (the square root of 2)B=AB=C/ (the square root of 2)C=A* (the square root of 2)C=B* (the square root of 2)All you math teachers out there- this works every time. I know it's not traditional, and there might be some building blocks it skips, but hey- it gets you to where you need to be.