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Find the sum of odd and even positions using one dimensional array? - Answers
easiest program #include<stdio.h> #include<conio.h> void main() { int sumeven=0,sumodd=0,arr[10],i; clrscr(); for(i=0;i<=9;i++) { scanf("%d",&arr[i]); } for(i=0;i<=9;i++) { if(i%2==0) { sumeven=sumeven+arr[i]; } else { sumodd=sumodd+arr[i]; } } printf(" sum of even position is %d",sumeven); printf(" sumof odd position is %d",sumodd); getch(); }
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Find the sum of odd and even positions using one dimensional array? - Answers
easiest program #include<stdio.h> #include<conio.h> void main() { int sumeven=0,sumodd=0,arr[10],i; clrscr(); for(i=0;i<=9;i++) { scanf("%d",&arr[i]); } for(i=0;i<=9;i++) { if(i%2==0) { sumeven=sumeven+arr[i]; } else { sumodd=sumodd+arr[i]; } } printf(" sum of even position is %d",sumeven); printf(" sumof odd position is %d",sumodd); getch(); }
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Find the sum of odd and even positions using one dimensional array? - Answers
easiest program #include<stdio.h> #include<conio.h> void main() { int sumeven=0,sumodd=0,arr[10],i; clrscr(); for(i=0;i<=9;i++) { scanf("%d",&arr[i]); } for(i=0;i<=9;i++) { if(i%2==0) { sumeven=sumeven+arr[i]; } else { sumodd=sumodd+arr[i]; } } printf(" sum of even position is %d",sumeven); printf(" sumof odd position is %d",sumodd); getch(); }
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