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Can you prove that area formula of hexagon? - Answers

Assume regular hexagon of side L. Split the hexagon into 6 equilateral triangles. (A sketch would help here) You need to find the height of the triangle to find it's area. Split the triangle in half with a vertical line. You now have 2 right angle triangles of base L/2 height h. Top angle 30 degrees, bottom angle 60 degrees. L/(2h) = tan 30 h = L/(2tan 30) h = root 3 L/2 Area of 1 equilateral triangle = 1/2 x L x h = (root 3 x L2)/4 Area of hexagon = 6x(root 3 x L2)/4 Area of hexagon = 3x(root 3 x L2)/2



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Can you prove that area formula of hexagon? - Answers

https://math.answers.com/math-and-arithmetic/Can_you_prove_that_area_formula_of_hexagon

Assume regular hexagon of side L. Split the hexagon into 6 equilateral triangles. (A sketch would help here) You need to find the height of the triangle to find it's area. Split the triangle in half with a vertical line. You now have 2 right angle triangles of base L/2 height h. Top angle 30 degrees, bottom angle 60 degrees. L/(2h) = tan 30 h = L/(2tan 30) h = root 3 L/2 Area of 1 equilateral triangle = 1/2 x L x h = (root 3 x L2)/4 Area of hexagon = 6x(root 3 x L2)/4 Area of hexagon = 3x(root 3 x L2)/2



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https://math.answers.com/math-and-arithmetic/Can_you_prove_that_area_formula_of_hexagon

Can you prove that area formula of hexagon? - Answers

Assume regular hexagon of side L. Split the hexagon into 6 equilateral triangles. (A sketch would help here) You need to find the height of the triangle to find it's area. Split the triangle in half with a vertical line. You now have 2 right angle triangles of base L/2 height h. Top angle 30 degrees, bottom angle 60 degrees. L/(2h) = tan 30 h = L/(2tan 30) h = root 3 L/2 Area of 1 equilateral triangle = 1/2 x L x h = (root 3 x L2)/4 Area of hexagon = 6x(root 3 x L2)/4 Area of hexagon = 3x(root 3 x L2)/2

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      Assume regular hexagon of side L. Split the hexagon into 6 equilateral triangles. (A sketch would help here) You need to find the height of the triangle to find it's area. Split the triangle in half with a vertical line. You now have 2 right angle triangles of base L/2 height h. Top angle 30 degrees, bottom angle 60 degrees. L/(2h) = tan 30 h = L/(2tan 30) h = root 3 L/2 Area of 1 equilateral triangle = 1/2 x L x h = (root 3 x L2)/4 Area of hexagon = 6x(root 3 x L2)/4 Area of hexagon = 3x(root 3 x L2)/2

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