math.answers.com/math-and-arithmetic/Can_the_magnitude_of_a_vector_be_lesser_than_its_component

Preview meta tags from the math.answers.com website.

Linked Hostnames

8

Thumbnail

Search Engine Appearance

Google

https://math.answers.com/math-and-arithmetic/Can_the_magnitude_of_a_vector_be_lesser_than_its_component

Can the magnitude of a vector be lesser than its component? - Answers

No, because the components along any other direction is v*cos(A) where v is the magnitude of the original vector and A is the angle between the direction of the original vector and the direction of the component. Since the absolute value of cos(A) cannot be greater than 1, then v*cos(A) cannot be greater than v.



Bing

Can the magnitude of a vector be lesser than its component? - Answers

https://math.answers.com/math-and-arithmetic/Can_the_magnitude_of_a_vector_be_lesser_than_its_component

No, because the components along any other direction is v*cos(A) where v is the magnitude of the original vector and A is the angle between the direction of the original vector and the direction of the component. Since the absolute value of cos(A) cannot be greater than 1, then v*cos(A) cannot be greater than v.



DuckDuckGo

https://math.answers.com/math-and-arithmetic/Can_the_magnitude_of_a_vector_be_lesser_than_its_component

Can the magnitude of a vector be lesser than its component? - Answers

No, because the components along any other direction is v*cos(A) where v is the magnitude of the original vector and A is the angle between the direction of the original vector and the direction of the component. Since the absolute value of cos(A) cannot be greater than 1, then v*cos(A) cannot be greater than v.

  • General Meta Tags

    22
    • title
      Can the magnitude of a vector be lesser than its component? - Answers
    • charset
      utf-8
    • Content-Type
      text/html; charset=utf-8
    • viewport
      minimum-scale=1, initial-scale=1, width=device-width, shrink-to-fit=no
    • X-UA-Compatible
      IE=edge,chrome=1

  • Open Graph Meta Tags

    7
    • og:image
      https://st.answers.com/html_test_assets/Answers_Blue.jpeg
    • og:image:width
      900
    • og:image:height
      900
    • og:site_name
      Answers
    • og:description
      No, because the components along any other direction is v*cos(A) where v is the magnitude of the original vector and A is the angle between the direction of the original vector and the direction of the component. Since the absolute value of cos(A) cannot be greater than 1, then v*cos(A) cannot be greater than v.

  • Twitter Meta Tags

    1
    • twitter:card
      summary_large_image

  • Link Tags

    16
    • alternate
      https://www.answers.com/feed.rss
    • apple-touch-icon
      /icons/180x180.png
    • canonical
      https://math.answers.com/math-and-arithmetic/Can_the_magnitude_of_a_vector_be_lesser_than_its_component
    • icon
      /favicon.svg
    • icon
      /icons/16x16.png

Links

58