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A man has a mixture of nickels dimes and quarters in his pocket. He has 12 coins in all with a total of $1.20. If he had twice as many dimes as quarters how many of each coin does he have? - Answers

Each quarter is 25, and he has X quarters. Each dime is 10, and he has 2X dimes. Each nickel is 5. He has 12 coins in total, and all of the ones that are not quarters or dimes are nickels. Since quarters and dimes have to come in sets of 3, that's 12-3X. 25X + 10(2X) + 5(12-3X) = 120 25X + 20X - 15X + 60 =120 30X + 60 = 120 30X = 60 X = 2 He has 2 quarters, 4 dimes, and 6 nickels. To double check let's add them up: (2 * 25) + (4* 10) + (6 * 5) = 120



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A man has a mixture of nickels dimes and quarters in his pocket. He has 12 coins in all with a total of $1.20. If he had twice as many dimes as quarters how many of each coin does he have? - Answers

https://math.answers.com/math-and-arithmetic/A-man-has-a-mixture-of-nickels-dimes-and-quarters-in-his-pocket-he-has-12-coins-in-all-with-a-total-of-$120-if-he-had-twice-as-many-dimes-as-quarters-how-many-of-each-coin-does-he-have

Each quarter is 25, and he has X quarters. Each dime is 10, and he has 2X dimes. Each nickel is 5. He has 12 coins in total, and all of the ones that are not quarters or dimes are nickels. Since quarters and dimes have to come in sets of 3, that's 12-3X. 25X + 10(2X) + 5(12-3X) = 120 25X + 20X - 15X + 60 =120 30X + 60 = 120 30X = 60 X = 2 He has 2 quarters, 4 dimes, and 6 nickels. To double check let's add them up: (2 * 25) + (4* 10) + (6 * 5) = 120



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https://math.answers.com/math-and-arithmetic/A-man-has-a-mixture-of-nickels-dimes-and-quarters-in-his-pocket-he-has-12-coins-in-all-with-a-total-of-$120-if-he-had-twice-as-many-dimes-as-quarters-how-many-of-each-coin-does-he-have

A man has a mixture of nickels dimes and quarters in his pocket. He has 12 coins in all with a total of $1.20. If he had twice as many dimes as quarters how many of each coin does he have? - Answers

Each quarter is 25, and he has X quarters. Each dime is 10, and he has 2X dimes. Each nickel is 5. He has 12 coins in total, and all of the ones that are not quarters or dimes are nickels. Since quarters and dimes have to come in sets of 3, that's 12-3X. 25X + 10(2X) + 5(12-3X) = 120 25X + 20X - 15X + 60 =120 30X + 60 = 120 30X = 60 X = 2 He has 2 quarters, 4 dimes, and 6 nickels. To double check let's add them up: (2 * 25) + (4* 10) + (6 * 5) = 120

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      A man has a mixture of nickels dimes and quarters in his pocket. He has 12 coins in all with a total of $1.20. If he had twice as many dimes as quarters how many of each coin does he have? - Answers
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      Each quarter is 25, and he has X quarters. Each dime is 10, and he has 2X dimes. Each nickel is 5. He has 12 coins in total, and all of the ones that are not quarters or dimes are nickels. Since quarters and dimes have to come in sets of 3, that's 12-3X. 25X + 10(2X) + 5(12-3X) = 120 25X + 20X - 15X + 60 =120 30X + 60 = 120 30X = 60 X = 2 He has 2 quarters, 4 dimes, and 6 nickels. To double check let's add them up: (2 * 25) + (4* 10) + (6 * 5) = 120

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