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3xpower of 2-6x plus 9? - Answers

If the question is to factor the problem, 3x2 - 6x + 9, then it can not be factored. If the question is to solve for x, assuming the equation is equal to zero, then use the quadratic formula with, a= 3 b= -6 c= 9 Then, 6 +- sqrt[36 - 4(3)(9)], all divided by 2(3) 6 +- sqrt[36 - 108] divided by 6 [6 +- sqrt(-72)] / 6 To reduce a negative square root, first pull out the negative one by using i, then find the perfect square in 72, which is 36, so the equation becomes: 6+- 6isqrt(2) / 6 Reduce the fraction and cancel the sixes 1 + i sqrt(2) AND 1 - i sqrt(2)



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3xpower of 2-6x plus 9? - Answers

https://math.answers.com/math-and-arithmetic/3xpower_of_2-6x_plus_9

If the question is to factor the problem, 3x2 - 6x + 9, then it can not be factored. If the question is to solve for x, assuming the equation is equal to zero, then use the quadratic formula with, a= 3 b= -6 c= 9 Then, 6 +- sqrt[36 - 4(3)(9)], all divided by 2(3) 6 +- sqrt[36 - 108] divided by 6 [6 +- sqrt(-72)] / 6 To reduce a negative square root, first pull out the negative one by using i, then find the perfect square in 72, which is 36, so the equation becomes: 6+- 6isqrt(2) / 6 Reduce the fraction and cancel the sixes 1 + i sqrt(2) AND 1 - i sqrt(2)



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https://math.answers.com/math-and-arithmetic/3xpower_of_2-6x_plus_9

3xpower of 2-6x plus 9? - Answers

If the question is to factor the problem, 3x2 - 6x + 9, then it can not be factored. If the question is to solve for x, assuming the equation is equal to zero, then use the quadratic formula with, a= 3 b= -6 c= 9 Then, 6 +- sqrt[36 - 4(3)(9)], all divided by 2(3) 6 +- sqrt[36 - 108] divided by 6 [6 +- sqrt(-72)] / 6 To reduce a negative square root, first pull out the negative one by using i, then find the perfect square in 72, which is 36, so the equation becomes: 6+- 6isqrt(2) / 6 Reduce the fraction and cancel the sixes 1 + i sqrt(2) AND 1 - i sqrt(2)

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      If the question is to factor the problem, 3x2 - 6x + 9, then it can not be factored. If the question is to solve for x, assuming the equation is equal to zero, then use the quadratic formula with, a= 3 b= -6 c= 9 Then, 6 +- sqrt[36 - 4(3)(9)], all divided by 2(3) 6 +- sqrt[36 - 108] divided by 6 [6 +- sqrt(-72)] / 6 To reduce a negative square root, first pull out the negative one by using i, then find the perfect square in 72, which is 36, so the equation becomes: 6+- 6isqrt(2) / 6 Reduce the fraction and cancel the sixes 1 + i sqrt(2) AND 1 - i sqrt(2)

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