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10101011 in terms of its number base? - Answers

That depends on what base the number is expressed in. Given the fact that you're using strictly ones and zeros, we might assume that you're using binary. That's not necessarily true though. That's also a perfectly valid number in decimal: ten million, one hundred and on thousand and eleven. In fact because it uses the smallest possible number of digits, it is a valid number in any base. Assuming though that you're referring to it as a binary number, it is - in terms of it's base: 1 * 27 + 0 * 26 + 1 * 25 + 0 * 24 + 1 * 23 + 0 * 22 + 1 * 21 + 1 * 20 = 128 + 32 + 8 + 2 + 1 = 171 (in decimal)



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10101011 in terms of its number base? - Answers

https://math.answers.com/math-and-arithmetic/10101011_in_terms_of_its_number_base

That depends on what base the number is expressed in. Given the fact that you're using strictly ones and zeros, we might assume that you're using binary. That's not necessarily true though. That's also a perfectly valid number in decimal: ten million, one hundred and on thousand and eleven. In fact because it uses the smallest possible number of digits, it is a valid number in any base. Assuming though that you're referring to it as a binary number, it is - in terms of it's base: 1 * 27 + 0 * 26 + 1 * 25 + 0 * 24 + 1 * 23 + 0 * 22 + 1 * 21 + 1 * 20 = 128 + 32 + 8 + 2 + 1 = 171 (in decimal)



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https://math.answers.com/math-and-arithmetic/10101011_in_terms_of_its_number_base

10101011 in terms of its number base? - Answers

That depends on what base the number is expressed in. Given the fact that you're using strictly ones and zeros, we might assume that you're using binary. That's not necessarily true though. That's also a perfectly valid number in decimal: ten million, one hundred and on thousand and eleven. In fact because it uses the smallest possible number of digits, it is a valid number in any base. Assuming though that you're referring to it as a binary number, it is - in terms of it's base: 1 * 27 + 0 * 26 + 1 * 25 + 0 * 24 + 1 * 23 + 0 * 22 + 1 * 21 + 1 * 20 = 128 + 32 + 8 + 2 + 1 = 171 (in decimal)

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      That depends on what base the number is expressed in. Given the fact that you're using strictly ones and zeros, we might assume that you're using binary. That's not necessarily true though. That's also a perfectly valid number in decimal: ten million, one hundred and on thousand and eleven. In fact because it uses the smallest possible number of digits, it is a valid number in any base. Assuming though that you're referring to it as a binary number, it is - in terms of it's base: 1 * 27 + 0 * 26 + 1 * 25 + 0 * 24 + 1 * 23 + 0 * 22 + 1 * 21 + 1 * 20 = 128 + 32 + 8 + 2 + 1 = 171 (in decimal)

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