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How do you draw a rectangle with an area of 12cm2? - Answers

Let B be any positive number less than sqrt(12) and let L = 12/B. Then a rectangle with sides of L cm and B cm will have an area of L*B = (12/B)*B = 12 cm2. Since there are infinitely many possible choices for B, there are infinitely many possible rectangles.



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How do you draw a rectangle with an area of 12cm2? - Answers

https://math.answers.com/geometry/How_do_you_draw_a_rectangle_with_an_area_of_12cm2

Let B be any positive number less than sqrt(12) and let L = 12/B. Then a rectangle with sides of L cm and B cm will have an area of L*B = (12/B)*B = 12 cm2. Since there are infinitely many possible choices for B, there are infinitely many possible rectangles.



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https://math.answers.com/geometry/How_do_you_draw_a_rectangle_with_an_area_of_12cm2

How do you draw a rectangle with an area of 12cm2? - Answers

Let B be any positive number less than sqrt(12) and let L = 12/B. Then a rectangle with sides of L cm and B cm will have an area of L*B = (12/B)*B = 12 cm2. Since there are infinitely many possible choices for B, there are infinitely many possible rectangles.

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      Let B be any positive number less than sqrt(12) and let L = 12/B. Then a rectangle with sides of L cm and B cm will have an area of L*B = (12/B)*B = 12 cm2. Since there are infinitely many possible choices for B, there are infinitely many possible rectangles.

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