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https://math.answers.com/geometry/A_rectangle_with_area_the_same_as_the_perimeter

A rectangle with area the same as the perimeter? - Answers

The perimeter of a rectangle can be expressed as [2 * ( L+ W )]. The area of a rectangle can be expressed as [L * W]. Thus, the equation can be written as:2 * ( L + W ) = L * WThe answer originally posted on this page suggested the only solution is when the shape of the rectangle (four-sided object, opposite sides are equal length) is a square (four-sided object, all sides are equal length) with sides equal to 4.Actually, a 6 x 3 (or 3 x 6) rectangle satisfies the equation, as it has an area and perimeter both equal to 18.Keep in mind this is considering the rectangle sides must have integer values (positive number that is not a fraction), which is actually in accordance with the way the problem was posed going back to its original roots.



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A rectangle with area the same as the perimeter? - Answers

https://math.answers.com/geometry/A_rectangle_with_area_the_same_as_the_perimeter

The perimeter of a rectangle can be expressed as [2 * ( L+ W )]. The area of a rectangle can be expressed as [L * W]. Thus, the equation can be written as:2 * ( L + W ) = L * WThe answer originally posted on this page suggested the only solution is when the shape of the rectangle (four-sided object, opposite sides are equal length) is a square (four-sided object, all sides are equal length) with sides equal to 4.Actually, a 6 x 3 (or 3 x 6) rectangle satisfies the equation, as it has an area and perimeter both equal to 18.Keep in mind this is considering the rectangle sides must have integer values (positive number that is not a fraction), which is actually in accordance with the way the problem was posed going back to its original roots.



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https://math.answers.com/geometry/A_rectangle_with_area_the_same_as_the_perimeter

A rectangle with area the same as the perimeter? - Answers

The perimeter of a rectangle can be expressed as [2 * ( L+ W )]. The area of a rectangle can be expressed as [L * W]. Thus, the equation can be written as:2 * ( L + W ) = L * WThe answer originally posted on this page suggested the only solution is when the shape of the rectangle (four-sided object, opposite sides are equal length) is a square (four-sided object, all sides are equal length) with sides equal to 4.Actually, a 6 x 3 (or 3 x 6) rectangle satisfies the equation, as it has an area and perimeter both equal to 18.Keep in mind this is considering the rectangle sides must have integer values (positive number that is not a fraction), which is actually in accordance with the way the problem was posed going back to its original roots.

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      The perimeter of a rectangle can be expressed as [2 * ( L+ W )]. The area of a rectangle can be expressed as [L * W]. Thus, the equation can be written as:2 * ( L + W ) = L * WThe answer originally posted on this page suggested the only solution is when the shape of the rectangle (four-sided object, opposite sides are equal length) is a square (four-sided object, all sides are equal length) with sides equal to 4.Actually, a 6 x 3 (or 3 x 6) rectangle satisfies the equation, as it has an area and perimeter both equal to 18.Keep in mind this is considering the rectangle sides must have integer values (positive number that is not a fraction), which is actually in accordance with the way the problem was posed going back to its original roots.
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