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https://math.answers.com/geometry/A_program_to_compute_the_real_roots_of_the_quadratic_equation

A program to compute the real roots of the quadratic equation? - Answers

Where the equation is ax2 + bx + c the roots are given by the solutions to : (-b +/- sqrt(b2 - 4ac))/2a So you would first input the values of a, b , and c, then calculate [d = b*b - 4*a*c], and then determine whether it is positive or negative. If it is positive [d>0, or d=0], then you can continue: so the two roots of x are: (-b + sqrt(d))/2/a, and (-b - sqrt(d))/2/a. If d < 0, then you need to calculate sqrt(-d) and then display -b/2/a as the real part, and +/- sqrt(-d)/2/a as the imaginary parts.



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A program to compute the real roots of the quadratic equation? - Answers

https://math.answers.com/geometry/A_program_to_compute_the_real_roots_of_the_quadratic_equation

Where the equation is ax2 + bx + c the roots are given by the solutions to : (-b +/- sqrt(b2 - 4ac))/2a So you would first input the values of a, b , and c, then calculate [d = b*b - 4*a*c], and then determine whether it is positive or negative. If it is positive [d>0, or d=0], then you can continue: so the two roots of x are: (-b + sqrt(d))/2/a, and (-b - sqrt(d))/2/a. If d < 0, then you need to calculate sqrt(-d) and then display -b/2/a as the real part, and +/- sqrt(-d)/2/a as the imaginary parts.



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https://math.answers.com/geometry/A_program_to_compute_the_real_roots_of_the_quadratic_equation

A program to compute the real roots of the quadratic equation? - Answers

Where the equation is ax2 + bx + c the roots are given by the solutions to : (-b +/- sqrt(b2 - 4ac))/2a So you would first input the values of a, b , and c, then calculate [d = b*b - 4*a*c], and then determine whether it is positive or negative. If it is positive [d>0, or d=0], then you can continue: so the two roots of x are: (-b + sqrt(d))/2/a, and (-b - sqrt(d))/2/a. If d < 0, then you need to calculate sqrt(-d) and then display -b/2/a as the real part, and +/- sqrt(-d)/2/a as the imaginary parts.

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      Where the equation is ax2 + bx + c the roots are given by the solutions to : (-b +/- sqrt(b2 - 4ac))/2a So you would first input the values of a, b , and c, then calculate [d = b*b - 4*a*c], and then determine whether it is positive or negative. If it is positive [d>0, or d=0], then you can continue: so the two roots of x are: (-b + sqrt(d))/2/a, and (-b - sqrt(d))/2/a. If d < 0, then you need to calculate sqrt(-d) and then display -b/2/a as the real part, and +/- sqrt(-d)/2/a as the imaginary parts.

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