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How do you figure out complex number problems? - Answers

It depends on what you're trying to do with the complex numbers, and what level of math understanding that you are at. Some tips:Treat the i like a variable (like x): example: Add a + bx & c + dx = a + bx + c + dx = a + c + bx + dx = (a + c) + (b + d)x. Now, substitute x = iMultiplying: (a + bx) * (c + dx) = ac + adx + bcx + bdx2 = ac + (ad + bc)x + bdx2, when substituting x = i in this one: ac + (ad + bc)i + bdi2, but i2 = -1, so we have:ac + (ad + bc)i - bd = (ac - bd) + (ad + bc)iIf you are familiar with vectors, you can treat complex numbers as vectors in the complex plane, and do some operations on them that way. See related link.



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How do you figure out complex number problems? - Answers

https://math.answers.com/basic-math/How_do_you_figure_out_complex_number_problems

It depends on what you're trying to do with the complex numbers, and what level of math understanding that you are at. Some tips:Treat the i like a variable (like x): example: Add a + bx & c + dx = a + bx + c + dx = a + c + bx + dx = (a + c) + (b + d)x. Now, substitute x = iMultiplying: (a + bx) * (c + dx) = ac + adx + bcx + bdx2 = ac + (ad + bc)x + bdx2, when substituting x = i in this one: ac + (ad + bc)i + bdi2, but i2 = -1, so we have:ac + (ad + bc)i - bd = (ac - bd) + (ad + bc)iIf you are familiar with vectors, you can treat complex numbers as vectors in the complex plane, and do some operations on them that way. See related link.



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https://math.answers.com/basic-math/How_do_you_figure_out_complex_number_problems

How do you figure out complex number problems? - Answers

It depends on what you're trying to do with the complex numbers, and what level of math understanding that you are at. Some tips:Treat the i like a variable (like x): example: Add a + bx & c + dx = a + bx + c + dx = a + c + bx + dx = (a + c) + (b + d)x. Now, substitute x = iMultiplying: (a + bx) * (c + dx) = ac + adx + bcx + bdx2 = ac + (ad + bc)x + bdx2, when substituting x = i in this one: ac + (ad + bc)i + bdi2, but i2 = -1, so we have:ac + (ad + bc)i - bd = (ac - bd) + (ad + bc)iIf you are familiar with vectors, you can treat complex numbers as vectors in the complex plane, and do some operations on them that way. See related link.

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      It depends on what you're trying to do with the complex numbers, and what level of math understanding that you are at. Some tips:Treat the i like a variable (like x): example: Add a + bx & c + dx = a + bx + c + dx = a + c + bx + dx = (a + c) + (b + d)x. Now, substitute x = iMultiplying: (a + bx) * (c + dx) = ac + adx + bcx + bdx2 = ac + (ad + bc)x + bdx2, when substituting x = i in this one: ac + (ad + bc)i + bdi2, but i2 = -1, so we have:ac + (ad + bc)i - bd = (ac - bd) + (ad + bc)iIf you are familiar with vectors, you can treat complex numbers as vectors in the complex plane, and do some operations on them that way. See related link.
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