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How do you factor x2 - x - 35? - Answers

Factors of 35 are 1 & 35 or 5 & 7. Can't get a -1 out of those so you have to use the quadratic formula: minus b +/- sqrt (b^2 - 4 x a x c) all over 2 x a. this gives (1 +/- sqrt (1+140) )/2 = (1 +/- 11.874)2 = 6.437 or -5.437 Check: 6.437^2 -6.437 = 41.435 - 6.437 = 34 .998. Near enough. If the original equation had been x^2 - 2x - 35 it would have factored nicely as (x + 5)(x -7)



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How do you factor x2 - x - 35? - Answers

https://math.answers.com/basic-math/How_do_you_factor_x2_-_x_-_35

Factors of 35 are 1 & 35 or 5 & 7. Can't get a -1 out of those so you have to use the quadratic formula: minus b +/- sqrt (b^2 - 4 x a x c) all over 2 x a. this gives (1 +/- sqrt (1+140) )/2 = (1 +/- 11.874)2 = 6.437 or -5.437 Check: 6.437^2 -6.437 = 41.435 - 6.437 = 34 .998. Near enough. If the original equation had been x^2 - 2x - 35 it would have factored nicely as (x + 5)(x -7)



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https://math.answers.com/basic-math/How_do_you_factor_x2_-_x_-_35

How do you factor x2 - x - 35? - Answers

Factors of 35 are 1 & 35 or 5 & 7. Can't get a -1 out of those so you have to use the quadratic formula: minus b +/- sqrt (b^2 - 4 x a x c) all over 2 x a. this gives (1 +/- sqrt (1+140) )/2 = (1 +/- 11.874)2 = 6.437 or -5.437 Check: 6.437^2 -6.437 = 41.435 - 6.437 = 34 .998. Near enough. If the original equation had been x^2 - 2x - 35 it would have factored nicely as (x + 5)(x -7)

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      Factors of 35 are 1 & 35 or 5 & 7. Can't get a -1 out of those so you have to use the quadratic formula: minus b +/- sqrt (b^2 - 4 x a x c) all over 2 x a. this gives (1 +/- sqrt (1+140) )/2 = (1 +/- 11.874)2 = 6.437 or -5.437 Check: 6.437^2 -6.437 = 41.435 - 6.437 = 34 .998. Near enough. If the original equation had been x^2 - 2x - 35 it would have factored nicely as (x + 5)(x -7)

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