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How do you factor the trinomial completely 18x3 29x 3x? - Answers

I'm guessing that's 18x3 + 29x2 + 3x. That factors to x(2x + 3)(9x + 1) 18x3 + 29x2 + 3x factor x = x(18x2 + 29x + 3) write 29x as 27x + 2x = x(18x2 + 27x + 2x + 3) group by two and factor each group = x[(18x2 + 27x) + (2x + 3)] = x[9x(2x + 3) + 1(2x + 3)] continue factoring = x(2x + 3)(9x + 1) Or since (18)(3) = 54 and (27)(2) = 54 then write: = x(18x2 + 29x + 3) = x[(18x + 27)/9][(18x + 2)/2] = x(2x + 3)(9x + 1)



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How do you factor the trinomial completely 18x3 29x 3x? - Answers

https://math.answers.com/basic-math/How_do_you_factor_the_trinomial_completely_18x3_29x_3x

I'm guessing that's 18x3 + 29x2 + 3x. That factors to x(2x + 3)(9x + 1) 18x3 + 29x2 + 3x factor x = x(18x2 + 29x + 3) write 29x as 27x + 2x = x(18x2 + 27x + 2x + 3) group by two and factor each group = x[(18x2 + 27x) + (2x + 3)] = x[9x(2x + 3) + 1(2x + 3)] continue factoring = x(2x + 3)(9x + 1) Or since (18)(3) = 54 and (27)(2) = 54 then write: = x(18x2 + 29x + 3) = x[(18x + 27)/9][(18x + 2)/2] = x(2x + 3)(9x + 1)



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https://math.answers.com/basic-math/How_do_you_factor_the_trinomial_completely_18x3_29x_3x

How do you factor the trinomial completely 18x3 29x 3x? - Answers

I'm guessing that's 18x3 + 29x2 + 3x. That factors to x(2x + 3)(9x + 1) 18x3 + 29x2 + 3x factor x = x(18x2 + 29x + 3) write 29x as 27x + 2x = x(18x2 + 27x + 2x + 3) group by two and factor each group = x[(18x2 + 27x) + (2x + 3)] = x[9x(2x + 3) + 1(2x + 3)] continue factoring = x(2x + 3)(9x + 1) Or since (18)(3) = 54 and (27)(2) = 54 then write: = x(18x2 + 29x + 3) = x[(18x + 27)/9][(18x + 2)/2] = x(2x + 3)(9x + 1)

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      I'm guessing that's 18x3 + 29x2 + 3x. That factors to x(2x + 3)(9x + 1) 18x3 + 29x2 + 3x factor x = x(18x2 + 29x + 3) write 29x as 27x + 2x = x(18x2 + 27x + 2x + 3) group by two and factor each group = x[(18x2 + 27x) + (2x + 3)] = x[9x(2x + 3) + 1(2x + 3)] continue factoring = x(2x + 3)(9x + 1) Or since (18)(3) = 54 and (27)(2) = 54 then write: = x(18x2 + 29x + 3) = x[(18x + 27)/9][(18x + 2)/2] = x(2x + 3)(9x + 1)

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