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https://math.answers.com/algebra/How_many_roots_does_the_polynomial_function_y(x-8)(x_3)2_have

How many roots does the polynomial function y(x-8)(x 3)2 have? - Answers

I assume that should read:y = (x-8)(x+3)^2 (where the "^" stands for power) Since the polynomial is already factored, it is clear that it has the roots 8, -3, and -3; in other words, three roots (including one double root); or two, if you count the duplicates only once.



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How many roots does the polynomial function y(x-8)(x 3)2 have? - Answers

https://math.answers.com/algebra/How_many_roots_does_the_polynomial_function_y(x-8)(x_3)2_have

I assume that should read:y = (x-8)(x+3)^2 (where the "^" stands for power) Since the polynomial is already factored, it is clear that it has the roots 8, -3, and -3; in other words, three roots (including one double root); or two, if you count the duplicates only once.



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https://math.answers.com/algebra/How_many_roots_does_the_polynomial_function_y(x-8)(x_3)2_have

How many roots does the polynomial function y(x-8)(x 3)2 have? - Answers

I assume that should read:y = (x-8)(x+3)^2 (where the "^" stands for power) Since the polynomial is already factored, it is clear that it has the roots 8, -3, and -3; in other words, three roots (including one double root); or two, if you count the duplicates only once.

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      I assume that should read:y = (x-8)(x+3)^2 (where the "^" stands for power) Since the polynomial is already factored, it is clear that it has the roots 8, -3, and -3; in other words, three roots (including one double root); or two, if you count the duplicates only once.

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