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How do you find zeros by factoring a function? - Answers

Each factor will contribute a zero. f(x) = Ax^2 + Bx + C will take the form of something like f(x) = (x-r1)(x-r2) when you factor it. Now the zeros are the values of x for which f(x) = 0. You know 0 times anything is zero, so consider one factor at a time. (x-r1) will equal zero when x = r1, therefore r1 is a "zero" (or "root") of f(x). Incidentally, f(x) = 0 when x = r1 because 0*(x-r2) = 0 for any value of r2. To find the second "zero" find the value of x that makes (x-r2) equal zero. If f(x) = (x+2)(x+3) then the zeros are -2 and -3, because f(-2) = 0 and f(-3) = 0. So if you can factor a function, you can easily find its zeros. The challenge is actually factoring the function.



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How do you find zeros by factoring a function? - Answers

https://math.answers.com/algebra/How_do_you_find_zeros_by_factoring_a_function

Each factor will contribute a zero. f(x) = Ax^2 + Bx + C will take the form of something like f(x) = (x-r1)(x-r2) when you factor it. Now the zeros are the values of x for which f(x) = 0. You know 0 times anything is zero, so consider one factor at a time. (x-r1) will equal zero when x = r1, therefore r1 is a "zero" (or "root") of f(x). Incidentally, f(x) = 0 when x = r1 because 0*(x-r2) = 0 for any value of r2. To find the second "zero" find the value of x that makes (x-r2) equal zero. If f(x) = (x+2)(x+3) then the zeros are -2 and -3, because f(-2) = 0 and f(-3) = 0. So if you can factor a function, you can easily find its zeros. The challenge is actually factoring the function.



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https://math.answers.com/algebra/How_do_you_find_zeros_by_factoring_a_function

How do you find zeros by factoring a function? - Answers

Each factor will contribute a zero. f(x) = Ax^2 + Bx + C will take the form of something like f(x) = (x-r1)(x-r2) when you factor it. Now the zeros are the values of x for which f(x) = 0. You know 0 times anything is zero, so consider one factor at a time. (x-r1) will equal zero when x = r1, therefore r1 is a "zero" (or "root") of f(x). Incidentally, f(x) = 0 when x = r1 because 0*(x-r2) = 0 for any value of r2. To find the second "zero" find the value of x that makes (x-r2) equal zero. If f(x) = (x+2)(x+3) then the zeros are -2 and -3, because f(-2) = 0 and f(-3) = 0. So if you can factor a function, you can easily find its zeros. The challenge is actually factoring the function.

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      Each factor will contribute a zero. f(x) = Ax^2 + Bx + C will take the form of something like f(x) = (x-r1)(x-r2) when you factor it. Now the zeros are the values of x for which f(x) = 0. You know 0 times anything is zero, so consider one factor at a time. (x-r1) will equal zero when x = r1, therefore r1 is a "zero" (or "root") of f(x). Incidentally, f(x) = 0 when x = r1 because 0*(x-r2) = 0 for any value of r2. To find the second "zero" find the value of x that makes (x-r2) equal zero. If f(x) = (x+2)(x+3) then the zeros are -2 and -3, because f(-2) = 0 and f(-3) = 0. So if you can factor a function, you can easily find its zeros. The challenge is actually factoring the function.
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