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How do you find the prime factorization of 88? - Answers

We note that '88' is an even number, because it ends in '8' , an even number. So it will divide by '2' Hence 2)88 2)44 2)22 11)11 =1 Reduce to '1' Then the prime factors are 2 x 2 x 2 x11 = 2^(3) x 11



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How do you find the prime factorization of 88? - Answers

https://math.answers.com/algebra/How_do_you_find_the_prime_factorization_of_88

We note that '88' is an even number, because it ends in '8' , an even number. So it will divide by '2' Hence 2)88 2)44 2)22 11)11 =1 Reduce to '1' Then the prime factors are 2 x 2 x 2 x11 = 2^(3) x 11



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https://math.answers.com/algebra/How_do_you_find_the_prime_factorization_of_88

How do you find the prime factorization of 88? - Answers

We note that '88' is an even number, because it ends in '8' , an even number. So it will divide by '2' Hence 2)88 2)44 2)22 11)11 =1 Reduce to '1' Then the prime factors are 2 x 2 x 2 x11 = 2^(3) x 11

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      We note that '88' is an even number, because it ends in '8' , an even number. So it will divide by '2' Hence 2)88 2)44 2)22 11)11 =1 Reduce to '1' Then the prime factors are 2 x 2 x 2 x11 = 2^(3) x 11

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