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How do you factorise 14xy-21x plus 7? - Answers

14xy - 21x + 7 '7' is a common factor to all three coefficients. So 'take it out'. Hence 7(2xy - 3x + 1) The rest of it , inside the brackets does not factor. However, I suspect the 'y' should be a 'power of 2' Hence 7(2x^(2) - 3x + 1) This factors to 7(2x - 1)(x - 1) Fully factored.!!!!



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How do you factorise 14xy-21x plus 7? - Answers

https://math.answers.com/algebra/How_do_you_factorise_14xy-21x_plus_7

14xy - 21x + 7 '7' is a common factor to all three coefficients. So 'take it out'. Hence 7(2xy - 3x + 1) The rest of it , inside the brackets does not factor. However, I suspect the 'y' should be a 'power of 2' Hence 7(2x^(2) - 3x + 1) This factors to 7(2x - 1)(x - 1) Fully factored.!!!!



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https://math.answers.com/algebra/How_do_you_factorise_14xy-21x_plus_7

How do you factorise 14xy-21x plus 7? - Answers

14xy - 21x + 7 '7' is a common factor to all three coefficients. So 'take it out'. Hence 7(2xy - 3x + 1) The rest of it , inside the brackets does not factor. However, I suspect the 'y' should be a 'power of 2' Hence 7(2x^(2) - 3x + 1) This factors to 7(2x - 1)(x - 1) Fully factored.!!!!

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      14xy - 21x + 7 '7' is a common factor to all three coefficients. So 'take it out'. Hence 7(2xy - 3x + 1) The rest of it , inside the brackets does not factor. However, I suspect the 'y' should be a 'power of 2' Hence 7(2x^(2) - 3x + 1) This factors to 7(2x - 1)(x - 1) Fully factored.!!!!

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