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How many different rectangles can you make with a area of 24? - Answers

Infinitely many. Select any number L, greater than sqrt(24) units an let B = 24/L. then the rectangle with sides measuring L and B will have an area of L*B = L*24/L = 24 square units. Also, B ≤ sqrt(24) ≤ L so that value of L gives a different rectangle. And, since there are infinitely many possible values for L, there are infinitely many possible rectangles.



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How many different rectangles can you make with a area of 24? - Answers

https://math.answers.com/math-and-arithmetic/How_many_different_rectangles_can_you_make_with_a_area_of_24

Infinitely many. Select any number L, greater than sqrt(24) units an let B = 24/L. then the rectangle with sides measuring L and B will have an area of L*B = L*24/L = 24 square units. Also, B ≤ sqrt(24) ≤ L so that value of L gives a different rectangle. And, since there are infinitely many possible values for L, there are infinitely many possible rectangles.



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https://math.answers.com/math-and-arithmetic/How_many_different_rectangles_can_you_make_with_a_area_of_24

How many different rectangles can you make with a area of 24? - Answers

Infinitely many. Select any number L, greater than sqrt(24) units an let B = 24/L. then the rectangle with sides measuring L and B will have an area of L*B = L*24/L = 24 square units. Also, B ≤ sqrt(24) ≤ L so that value of L gives a different rectangle. And, since there are infinitely many possible values for L, there are infinitely many possible rectangles.

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      Infinitely many. Select any number L, greater than sqrt(24) units an let B = 24/L. then the rectangle with sides measuring L and B will have an area of L*B = L*24/L = 24 square units. Also, B ≤ sqrt(24) ≤ L so that value of L gives a different rectangle. And, since there are infinitely many possible values for L, there are infinitely many possible rectangles.

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