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How do you figure out 87 raised to the x equals 0.5? - Answers

87^x = 0.5 take the log of both sides: log(87^x) = log(0.5) according to one of the log laws, you can move exponents to the front of the log function, so: x(log87) = log(0.5) so, then you have to get x by itself, so divide... x = log(0.5)/log(87) x= -0.1552 so, to prove this: 87^(-0.1552)= 0.499997 (Close enough, I just rounded in the middle, but this answer would be more than acceptable)



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How do you figure out 87 raised to the x equals 0.5? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_figure_out_87_raised_to_the_x_equals_0.5

87^x = 0.5 take the log of both sides: log(87^x) = log(0.5) according to one of the log laws, you can move exponents to the front of the log function, so: x(log87) = log(0.5) so, then you have to get x by itself, so divide... x = log(0.5)/log(87) x= -0.1552 so, to prove this: 87^(-0.1552)= 0.499997 (Close enough, I just rounded in the middle, but this answer would be more than acceptable)



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https://math.answers.com/math-and-arithmetic/How_do_you_figure_out_87_raised_to_the_x_equals_0.5

How do you figure out 87 raised to the x equals 0.5? - Answers

87^x = 0.5 take the log of both sides: log(87^x) = log(0.5) according to one of the log laws, you can move exponents to the front of the log function, so: x(log87) = log(0.5) so, then you have to get x by itself, so divide... x = log(0.5)/log(87) x= -0.1552 so, to prove this: 87^(-0.1552)= 0.499997 (Close enough, I just rounded in the middle, but this answer would be more than acceptable)

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      87^x = 0.5 take the log of both sides: log(87^x) = log(0.5) according to one of the log laws, you can move exponents to the front of the log function, so: x(log87) = log(0.5) so, then you have to get x by itself, so divide... x = log(0.5)/log(87) x= -0.1552 so, to prove this: 87^(-0.1552)= 0.499997 (Close enough, I just rounded in the middle, but this answer would be more than acceptable)

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