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https://math.answers.com/geometry/How_many_rectangles_have_an_area_of_24cm_squared

How many rectangles have an area of 24cm squared? - Answers

Infinitely many. Suppose the length of the rectangle is L cm where L >= sqrt(24) = 4.899 cm (approx). Let the breadth of the rectangle be B = 24/L. Then area = L*B = L*24/L = 24 Since there are infinitely many choices for L, there are infinitely many rectangles. For example, 5 * 4.8 6 * 4 8 * 3 50* 0.48 60 * 0.4 600 * 0.04 6000 * 0.004 60000 * 0.0004 etc



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How many rectangles have an area of 24cm squared? - Answers

https://math.answers.com/geometry/How_many_rectangles_have_an_area_of_24cm_squared

Infinitely many. Suppose the length of the rectangle is L cm where L >= sqrt(24) = 4.899 cm (approx). Let the breadth of the rectangle be B = 24/L. Then area = L*B = L*24/L = 24 Since there are infinitely many choices for L, there are infinitely many rectangles. For example, 5 * 4.8 6 * 4 8 * 3 50* 0.48 60 * 0.4 600 * 0.04 6000 * 0.004 60000 * 0.0004 etc



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https://math.answers.com/geometry/How_many_rectangles_have_an_area_of_24cm_squared

How many rectangles have an area of 24cm squared? - Answers

Infinitely many. Suppose the length of the rectangle is L cm where L >= sqrt(24) = 4.899 cm (approx). Let the breadth of the rectangle be B = 24/L. Then area = L*B = L*24/L = 24 Since there are infinitely many choices for L, there are infinitely many rectangles. For example, 5 * 4.8 6 * 4 8 * 3 50* 0.48 60 * 0.4 600 * 0.04 6000 * 0.004 60000 * 0.0004 etc

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      Infinitely many. Suppose the length of the rectangle is L cm where L >= sqrt(24) = 4.899 cm (approx). Let the breadth of the rectangle be B = 24/L. Then area = L*B = L*24/L = 24 Since there are infinitely many choices for L, there are infinitely many rectangles. For example, 5 * 4.8 6 * 4 8 * 3 50* 0.48 60 * 0.4 600 * 0.04 6000 * 0.004 60000 * 0.0004 etc

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